Let $H=I-2ww^t$ be the Householder transformation such that
$H\begin{bmatrix}-24\\0\\7\end{bmatrix}=\begin{bmatrix}25\\0\\0\end{bmatrix}$
what is w?
Now I know H is involutory and orthogonal so $H^2=H^TH=I$ and H is symmetric $H=H^T$. So I can have HA=B and A=HB. That will give me a lot of equations to solve. Is there another (shorter) way of doing this?
Well, from this equation you see that
$$ -49 = 2w_1(-24w_1 + 7w_3), \quad 0 = 2w_2(-24w_1 + 7w_3), \quad\text{and}\quad 7 = 2w_3(-24w_1 + 7w_3) $$
Multiplying the first equation by $w_3$ and the third equation by $w_1$ it follows that $w_1 = -7w_3$. Thus you get
$$ w_3 = \pm \frac{1}{\sqrt{50}} \implies w_1 = \mp\frac{7}{\sqrt{50}} \quad\text{and}\quad w_2 = 0 $$