here is a figure (fig_1) illustrating a space-filling spiral curve constitutes a triangle.
i am trying to draw this mathematically.
with @David K's help, we got this figure (fig_2)
by using this formula
\begin{align} &(-r, r) \\ &(r,-r) \\ &(-r,-r) \\ &(-2r,2r) \\ &(2r,-2r) \\ &(-2r,-2r) \\ &(-3r,3r) \\ &(3r,-3r) \\ &(-3r,-3r) \\ &(-4r,4r) \\ &(4r,-4r) \\ &(-4r,-4r) \\ &\ldots \end{align}
here is a piece of python code to implement the formula
import numpy as np
x = np.array([])
y = np.array([])
for r in range(1,9):
x = np.append(x, np.array([-r,r,-r]))
y = np.append(y, np.array([r,-r,-r]))
plt.plot(x,y)
fig_2 is very close to fig_1 though, there seems to be a bug. how to improve this formula?


thanks to @David K
doubling all the positive coordinates might work better
outputs
enter image description here