How can I find $\int \frac{1}{\sqrt{x^2 + x + 1}} dx$

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My question is, how can I evaluate the following integral? Am I supposed to use Euler substitution here or is there a simpler way?

$$\int \frac{1}{\sqrt{x^2 + x + 1}} dx$$

Thanks.

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Hint:

By completing the square and rescaling the variable, you will reduce the radicand to the form $t^2+1$, which calls for an inverse hyperbolic sine.