In order to solve $\zeta(x)=2$ we may use $\zeta(2)=\frac{\pi^2}{6}$ and $\zeta(s)=\frac{1}{s-1}+\gamma+o(1)$ for $s\to 1^+$. $\zeta(s)$ is decreasing and convex on $(1,2)$, hence Newton's method
$$ x \mapsto x-\frac{\zeta(x)-2}{\zeta'(x)} $$
with starting point $x=2$ (or, better, $\frac{3-\gamma}{2-\gamma}$) converges pretty fast to $1.72865\ldots$
In order to solve $\zeta(x)=2$ we may use $\zeta(2)=\frac{\pi^2}{6}$ and $\zeta(s)=\frac{1}{s-1}+\gamma+o(1)$ for $s\to 1^+$.
$\zeta(s)$ is decreasing and convex on $(1,2)$, hence Newton's method $$ x \mapsto x-\frac{\zeta(x)-2}{\zeta'(x)} $$ with starting point $x=2$ (or, better, $\frac{3-\gamma}{2-\gamma}$) converges pretty fast to $1.72865\ldots$