How can I find this integral? please help
$$I=\int_0^1\frac{e^{-\sqrt{x}}}{\sqrt{x}}\ dx.$$
2026-05-16 03:28:15.1778902095
How can I find this integral
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Set $\displaystyle\sqrt x=u\implies \frac{dx}{2\sqrt x}=du$
When $x=0,u=0$ and for $x=1,u=\sqrt1=1$
$$I=2\int_0^1e^{-u}du=2\cdot\frac{e^{-u}}{-1}\large|_0^1$$