How can I make a matrix form when $\Bbb{R}^3 \to \Bbb{R}^4$ is one-to-one?

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Problem : if $T: \Bbb{R}^3\to \Bbb{R}^4$ is one-to-one, describe the possible echelon forms of the standard matrix for a linear transformation $T$.

My solution is below.

To be one-to-one every column vectors must be independent, it means every columns must have pivot position. So I can form like this. $$ \begin{pmatrix} a&*&*\\ 0&b&*\\ 0&0&c\\ 0&0&0 \end{pmatrix} $$

Am I right? If not, how can I approach this problem?