given that:
$$\left(\limsup\limits_{n\rightarrow\infty}\left(\frac{1}{x_n}\right)\right)\cdot \left(\limsup\limits_{n\rightarrow\infty}(x_n)\right)=1$$
How can i prove that $x_n$ convergences?
I don't have ideas..
given that:
$$\left(\limsup\limits_{n\rightarrow\infty}\left(\frac{1}{x_n}\right)\right)\cdot \left(\limsup\limits_{n\rightarrow\infty}(x_n)\right)=1$$
How can i prove that $x_n$ convergences?
I don't have ideas..
See my comment above, we need the further hypothesis $x_n >0$ (eventually).
Call $L = \limsup_{n \to \infty} x_n$. By your condition, and our hypothesis we have clearly $0 <L < \infty$. In particular $L^{-1} = \limsup_{n \to \infty} x_n^{-1}$.
Now, it comes the key point: you have to show, only using definitions, that $$ \limsup_{n \to \infty} \ x_n^{-1} = \left( \liminf_{n \to \infty} \ x_n \right)^{-1}$$ I leave this exercize to you, since the solution depends on what definition of $\limsup$ you are familiar with. Hence, we have that $$\liminf_{n \to \infty} x_n=L = \limsup_{n \to \infty} x_n$$ and this concludes the proof.