Given
$$F\{\mu\} = \int f(t)e^{-j2\pi\mu t} dt $$
Show that
$$F\{f(t \pm t0)\} = e^{\pm j2\pi \mu t_0}F\{\mu\}$$
Do I have to solve this by using this formula?
$$\int f(t)e^{−j2!μt}dt =\int f(t)[cos(2\pi\mu t) − jsin(2\pi\mu t)]dt$$
Is there any easier way to prove this problem?