Can someone please show me with steps on how to evaluate this indefinite integral?
2026-05-02 09:11:36.1777713096
How can I solve this indefinite integral?
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Let $u = \sin x \implies du = \cos x\,dx$.
$$\int 3(\,\underbrace{\sin(x)}_{u}\,)^3 \,\underbrace{\cos x\,dx}_{du}= \int 3u^3 \,du$$