How can I solve $z^n = z^\ast$

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Where z is a complex number in the form $z = a+bi$, and $n\in \mathbb{R}$. I was capable of solving this for $z^2 = z^\ast$ by expanding both sides. But I was wondering if there was a way to solve for all n.

The answers I got for $z^2 = z^\ast$ were: $$ z= 0$$ $$ z= 1$$ $$ z= -\frac{1}{2} + \frac{\sqrt3}{2}i$$ $$ z= -\frac{1}{2} - \frac{\sqrt3}{2}i$$