Suppose we know the root system/Cartan matrix of a semisimple Lie algebra. Is there a formula that determines the dimension of the Lie algebra?
Thanks in advance.
Suppose we know the root system/Cartan matrix of a semisimple Lie algebra. Is there a formula that determines the dimension of the Lie algebra?
Thanks in advance.
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I assume you are talking about a split semisimple Lie algebra. This is always the case if you work over an algebraically closed field of characteristic $0$, like $\Bbb C$.
Then it's part of the standard structure theory that such a Lie algebra $L$ decomposes as
$$ L \simeq H \oplus \bigoplus_{\alpha \in R} L_\alpha$$
where $H$ is a Cartan subalgebra, $R$ is the corresponding root system, and $L_\alpha$ is the root space to the root $\alpha$. It's also a standard fact that in this case, all $L_\alpha$ are one-dimensional, whereas the dimension of $H$ equals the rank of $R$. Which implies
$$dim(L) = rank(R) + \lvert R \rvert.$$