How can the logistic equation be discretized to obtain the logistic map?

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The logistic equation is given by $$\frac{dP}{dt} = rP(1-P)$$

With the forward Euler method it can be intuitively discretized to $$P(t+h)-P(t) = hrP(t)(1-P(t))$$

Setting h=1 and $P(t) = P_{n}$ one obtains the following form. $$\Delta P_{n} = rP_{n}(1-P_{n}) $$

Which is what an intuition behind the logistic equation says: the change in a population P is proportional to P with rate r (resulting in exponential growth), but is hindered by the carrying capacity K=1 giving an additional term proportional to $-P^2$.

The logistic map is given by $$P_{n+1} = \alpha P_{n}(1-P_{n}) $$

Setting $\alpha = 1+r$ is a way to end up at the differential equation again, but the interpretation becomes a different one.

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If we try to squeeze the $P_n^2$ into the parenthesis, we can obtain

$$P_{n+1}-P_n=rP_n(1-P_n-{P_n\over r})$$

Now, we try to squeeze LHS's $P_n$ into the parenthesis, w obtain:

$$P_{n+1}=rP_n(1+{1\over r}-P_n-{P_n\over r})$$

Now, if we try to move the $r$ terms out, we can find this neat equation:

$$P_{n+1}=r\left(1+{1\over r}\right)P_n(1-P_n)=(r+1)P_n(1-P_n)$$

Since $r$ is some constant, we can now let $k=r+1$, so the logistic equation becomes logistic relation:

$$P_{n+1}=kP_n(1-P_n)$$

I hope this will help you.