How can I transform the product 365(15^2+16^2) into sum of two squares???
2026-03-31 10:08:39.1774951719
How can transform a product into sum of two squares
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See How do you prove that a prime is the sum of two squares iff it is congruent to 1 mod 4?
As $365=5\cdot73$
$5=1^2+2^2$
$73=8^2+3^2$
Use Brahmagupta-Fibonacci Identity $$(a^2+b^2)(c^2+d^2)=(ac\pm bd)^2+(ad\mp bc)^2$$