How can we find the distribution of the random variable defined in piece-wise?

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Find the distribution function of the random variable defined as follows,

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Let, $\Omega = [0, 3]$ and $\Bbb P$ is probability on $\Omega$.

I guess, this question wants me to find out CDF of $X$.

How should I solve this?

$\int_0^1(2\omega+1) d\omega = 2 ---------------------(i)$

$\int_1^2(\omega^2-1) d\omega = \frac{4}{3} ---------------------(ii)$

$(i)+(ii)+3 = (2 + \frac{4}{3}+3) = \frac{19}{3}$ Ans.

Am I getting somewhere?

I guess, No.