How can we get the approximate values $a,b,c$?
The condition and relation are the followings :
$0 < a,b,c < 1$
$a + b + c = 1$
$(1-a)^2 + b^2 + c^2 =1 $
How can we get the approximate values $a,b,c$?
The condition and relation are the followings :
$0 < a,b,c < 1$
$a + b + c = 1$
$(1-a)^2 + b^2 + c^2 =1 $
You don't need to approximate. You can simplify 2 and 3 together to give
$b^2 + bc + c^2 = \frac{1}{2}$
Combine that with 1 and you get an infinite set of solutions, one that has a completely defined relation between $b$ and $c$, with actually tighter limits on $b$ and $c$. $a$ is always just $1 - (b+c)$.