Let $H, K$ be subgroups of a finite group $G$ with $K \subset N_H$. Show that $$\#(HK) = \frac{\#(H)\#(K)}{\#(H \cap K)}$$
What would I need to do to prove this equation true?
Thanks in advance.
Let $H, K$ be subgroups of a finite group $G$ with $K \subset N_H$. Show that $$\#(HK) = \frac{\#(H)\#(K)}{\#(H \cap K)}$$
What would I need to do to prove this equation true?
Thanks in advance.
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If $K\subseteq N_G(H)$, and of course $H\subseteq N_G(H)$, you have $HK\subseteq N_G(H)$, and so $H\lhd HK$.
Simply by counting items in cosets you always have that $|G/N||N|=|G|$ in finite groups, where $N\lhd G$. Rewritten this says $|G/N|=|G|/|N|$
In this case, the second isomorphism theorem says that
$$HK/H\cong K/(H\cap K)$$
Applying the first observation, $|HK|/|H|=|K|/|H\cap K|$.
Multiplying by $|H|$ on both sides, you have your equation.