I have the following funtion: f(x) = 3-½√(6-4x)
Now, I would have no idea how to calculate the derivative and the answer booklet doesn't make it any more obvious because according to the answers it should be:
f'(x) = 0-½ . -4 . 1/2√(6-4x) = 1/(√6-4x)
can anyone explain to me what is happening and how they get to this answer?
HINT
Use that by chain rule
$$f(x)=c+\sqrt{g(x)}\implies f’(x)=\frac{g’(x)}{2\sqrt{g(x)}}$$