How do I simplify this fraction :
$$\frac{(3x^2+4x)\sqrt {x+1}}{2(x+1)^2}$$
The final result is $\frac{3x^2+4x} {2(x+1)^{3/2}}$.
How do I simplify this fraction :
$$\frac{(3x^2+4x)\sqrt {x+1}}{2(x+1)^2}$$
The final result is $\frac{3x^2+4x} {2(x+1)^{3/2}}$.
You divide the numerator and the denominator by $\sqrt{x+1}$, which gives the desired result.