I have $$y = x^{-t/s}$$
How do I solve for $t$ and $s$ in terms of the other variables?
Take the logarithm of both sides of the equation.
$$y = x^{-t/s} \iff \ln y = \ln\Big(x^{-t/s}\Big)$$
Now use a key property of logarithms to extract $-t/s$ from the exponent of $x$: $$\ln(a^b) = b\ln a$$
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Take the logarithm of both sides of the equation.
$$y = x^{-t/s} \iff \ln y = \ln\Big(x^{-t/s}\Big)$$
Now use a key property of logarithms to extract $-t/s$ from the exponent of $x$: $$\ln(a^b) = b\ln a$$