How do I solve this boundary-value problem?

53 Views Asked by At

There is no exact answer for this question, but I'm having trouble with guessing what the author intended.

Solve the boundary-value problem:

$u_{tt} = c^2 u_{xx} + u$

Boundary condition: $u(x,0)=f(x), u_t(x,0)=0, u(0,t)=0, u(l,t)=0$.

This problem is an exercise in an elementary differential equation text and I don't get what the author intended.

Here's how I tried this:

Set $u(x,t)=X(x)T(t)$.

Then, $\frac{X''}{X}=\frac{T'' - T}{c^2 T}$.

Thus for some constant $\lambda$, $X''+\lambda X =0 $ and $T'' + (c^2\lambda - 1)T=0$.

So $\lambda=\lambda_n=\frac{n^2\pi^2}{l^2}$ and $X(x)=X_n(x)=\sin (\frac{n\pi x}{l})$.

However, I have a trouble with finding $T_n$. There may be a case that $c^2 \lambda_n - 1 \leq 0$ for some $n$. So I think it should be assumed that $c^2 > l^2/\pi^2$.

If this is not the author intended, how do I solve this?