The question is- Find $\int\frac{\sec^xx}{\sqrt{\tan x}}dx$
What I've tried: $$\int\frac{\sec^{x-2}x\sec^2x}{\sqrt{\tan x}}dx$$
Let $\tan x = t$.
$$\int\frac{\sec^{x-2}x}{\sqrt{t\,}}dt$$
What should I do next? Any sort of help is appreciated.
The question is- Find $\int\frac{\sec^xx}{\sqrt{\tan x}}dx$
What I've tried: $$\int\frac{\sec^{x-2}x\sec^2x}{\sqrt{\tan x}}dx$$
Let $\tan x = t$.
$$\int\frac{\sec^{x-2}x}{\sqrt{t\,}}dt$$
What should I do next? Any sort of help is appreciated.
You can't. Integrands of the form $f^x(x)$ usually have no closed-form antiderivative, by the Liouville theorem.
The probability that your problem statement is wrong equals $1-\epsilon$.
And IMO the probability that the true question is
$$\int\frac{\sec^2x}{\sqrt{\tan x}}dx$$
equals $1+\epsilon$.