$$\lim\limits_{x\to 2} \frac{ 2x^2-5x+2 }{ \sqrt{2+x}-\sqrt{2x} }$$
Thanks
note that $$2x^2-5x+2=(2x-1)(x-2)$$ and we have by multiplication of numerator and denominator with $\sqrt{2+x}+\sqrt{2x}$ the following term $$\frac{(2x-1)(x-2)(\sqrt{2+x}+\sqrt{2x})}{-(x-2)}$$
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note that $$2x^2-5x+2=(2x-1)(x-2)$$ and we have by multiplication of numerator and denominator with $\sqrt{2+x}+\sqrt{2x}$ the following term $$\frac{(2x-1)(x-2)(\sqrt{2+x}+\sqrt{2x})}{-(x-2)}$$