how do can i get $(-2+i)$ e^$\pi$i/3 in the form $a+bi$ where $a$ and $b$ are in the set of real numbers $R$
any help would be greatly appreciated thank you
how do can i get $(-2+i)$ e^$\pi$i/3 in the form $a+bi$ where $a$ and $b$ are in the set of real numbers $R$
any help would be greatly appreciated thank you
HINT:
Use Euler Formula for $\displaystyle e^{\frac{i\pi}3}$
Finally, $(a+ib)(c+id)=ac-bd+i(ad+bc)$