$$\require{mhchem}\ce{NaOH + H2SO4 -> Na2SO4 + H2O}$$
I'm trying all my best to come up with one solution but cant. in giving the integer solution to this chemical equation is it compulsory?
$$\require{mhchem}\ce{NaOH + H2SO4 -> Na2SO4 + H2O}$$
I'm trying all my best to come up with one solution but cant. in giving the integer solution to this chemical equation is it compulsory?
Denote the numbers on the left with $a$ and $b$ and on the right with $c$ and $d$.
This leads to the system
$$a=2c$$ $$b=c$$ $$a+2b=2d$$ $$a+4b=4c+d$$
considering the number of Na,S,H and O-atoms.
This can also be written as
$\pmatrix {1&0&-2&0\\0&1&-1&0\\1&2&0&-2\\1&4&-4&-1} \pmatrix{a\\b\\c\\d}=\pmatrix{0\\0\\0\\0}$
The kernel of the matrix is $t\pmatrix{2\\1\\1\\2}$, so $(2,1,1,2)$ is the solution.
An easier way to solve the system is to simply start with $b=1$. Then you easily get the solution. If fractions would occur, this would also be no problem because any multiple of a solution is again a solution.