$$(\frac{-\sqrt{3}}{2}+\frac{1}{2}i)^{123}=i$$
$$(\frac{-3}{\sqrt{2}}+\frac{-3}{\sqrt{2}}i)^{11}=\frac{3^{11}}{\sqrt{2}}-\frac{3^{11}}{\sqrt{2}}i$$
So I have these equations with the answers already. I was wondering, how do you get them? What patterns should I look?
One way is to express them in polar form, so $\frac{-3}{\sqrt{2}}+\frac{-3}{\sqrt{2}}i=3e^{i\frac {5\pi}4}$. Then you can use the law for the power of a power $$(\frac{-3}{\sqrt{2}}+\frac{-3}{\sqrt{2}}i)^{11}=(3e^{i\frac {5\pi}4})^{11}=3^{11}e^{i\frac{55\pi}4}=\frac{3^{11}}{\sqrt{2}}-\frac{3^{11}}{\sqrt{2}}i$$