How do you confirm solutions to a PDE?

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The question is as follows:

Consider the following partial differntial equation (PDE)

$2\frac{\partial^2u}{\partial x^2}+2\frac{\partial^2u}{\partial y^2} = u$

where $u=u(x,y)$ is the unknown function.

Define the following functions:

$u_1(x,y):=xy^2, u_2(x,y)=\sin(xy)$ and $u_3(x,y)=e^{\frac{1}{3}(x-y)}$

Which of these functions are solutions to the above PDE?

Any walkthroughs, description of methods, links to resources would be highly appreciated.

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Same as you would an ordinary differential equation.

For each of $u_1,u_2,u_3$, do the following for this equation:

  • Calculate the relevant partial derivatives: that is, find $(u_1)_{xx},(u_1)_{yy},(u_2)_{xx},(u_2)_{yy},(u_3)_{xx},(u_3)_{yy}$

  • Substitute these values into the original PDE (which is $2u_{xx} + 2u_{yy} = u$): you're just picking $u = u_1$ when you use $u_1$ as the potential solution, and $u=u_2$ and $u=u_3$ in the other cases.

  • Substitute in the corresponding function $u_1$ or $u_2$ or $u_3$ for $u$.

Remember that function equality necessitates equality for all inputs for the functions. Thus, you should either ...

  • ...perform manipulations algebraically to try and arrive at a true statement. For example, if you did manipulations and concluded with $1=1$ or whatever, then the two functions are equal (translating to the function you used being a solution).

  • ...see if there's an input for which the two sides are not equal. For example, if I had, more simply, wanted to check if $x^2 = x^9$, I could see that if I put in $x=1/2$ I get two very different values. Thus the functions are not equal (which would translate into $u_1$ or $u_2$ or $u_3$, whichever you used, not being a valid solution).

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  • $2\cdot0+2\cdot2x=xy^2$ ?

  • $2(-y^2\sin(xy))+2(-x^2\sin(xy))=\sin(xy)$ ?

  • $2\dfrac{e^{(x-y)/3}}9+2\dfrac{e^{(x-y)/3}}9=e^{(x-y)/3}$ ?