I am stuck with this question below, I need help;
Here is how. First use the trigonometric identity
$$ \sin(at+b) = \sin(at)\cos(b) + \cos(at)\sin(b).$$
to expand the trig. expression you have then we need Hilbert transform of $\sin(at)$ and $\cos(at)$ (assuming $a>0$) which are given respectively by
$$ \cos(as)\quad \rm {and} \quad -\sin(as) $$
I think you can advance now.
Note:
1) I only considered the case $a>0$. For the case $a<0$ Hilbert transform of $\sin(at)$ and $\cos(at)$ will be given by
$$ -\cos(as)\quad \rm {and} \quad \sin(as) $$
2) The Hilbert transform is defined as
$$ H[f(x)]=\frac{1}{\pi} \rm{pv}\, \int_{-\infty}^{\infty}\frac{f(x)}{x-y}dx. $$
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Here is how. First use the trigonometric identity
to expand the trig. expression you have then we need Hilbert transform of $\sin(at)$ and $\cos(at)$ (assuming $a>0$) which are given respectively by
I think you can advance now.
Note:
1) I only considered the case $a>0$. For the case $a<0$ Hilbert transform of $\sin(at)$ and $\cos(at)$ will be given by
2) The Hilbert transform is defined as