Several algorithms exist to find the primitive roots of prime numbers. How does one find the primitive roots of a non-prime number?
2026-03-29 10:18:07.1774779487
How does one find the primitive roots of a non-prime number?
3.4k Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail At
1
There are 1 best solutions below
Related Questions in PRIMITIVE-ROOTS
- Exercise 34 from Needham Visual Complex Analysis 1. Cyclotomic polynomial for the pth (p prime )root of unity
- Smallest prime $p$ which every integer $< n$ is a primitive root $\mod p$
- On multiplicative and additive properties of cyclotomic polynomials
- Showing two different definitions of a primitive root are the same
- Prove $\sum\limits_{j=1}^{p-1} j\left(\frac{j}{p}\right) = 0 $ for an odd prime $p$ with $p\equiv 1\text{ mod } 4$
- must a primitive root be invertible?
- Efficient algorithms for Primitive roots where time-complexity is $\leq O(\sqrt{n})$
- Question related to N-th cyclotomic polynomial, principal N-th root of unity and residue class of X
- How to show the $p$ minus primitive root is also a primitive root for $p \equiv1 \pmod {4}$
- Find a primitive root of (a) $U(\mathbb{Z}/121\mathbb{Z})$, and (b) $U(\mathbb{Z}/18\mathbb{Z})$
Trending Questions
- Induction on the number of equations
- How to convince a math teacher of this simple and obvious fact?
- Find $E[XY|Y+Z=1 ]$
- Refuting the Anti-Cantor Cranks
- What are imaginary numbers?
- Determine the adjoint of $\tilde Q(x)$ for $\tilde Q(x)u:=(Qu)(x)$ where $Q:U→L^2(Ω,ℝ^d$ is a Hilbert-Schmidt operator and $U$ is a Hilbert space
- Why does this innovative method of subtraction from a third grader always work?
- How do we know that the number $1$ is not equal to the number $-1$?
- What are the Implications of having VΩ as a model for a theory?
- Defining a Galois Field based on primitive element versus polynomial?
- Can't find the relationship between two columns of numbers. Please Help
- Is computer science a branch of mathematics?
- Is there a bijection of $\mathbb{R}^n$ with itself such that the forward map is connected but the inverse is not?
- Identification of a quadrilateral as a trapezoid, rectangle, or square
- Generator of inertia group in function field extension
Popular # Hahtags
second-order-logic
numerical-methods
puzzle
logic
probability
number-theory
winding-number
real-analysis
integration
calculus
complex-analysis
sequences-and-series
proof-writing
set-theory
functions
homotopy-theory
elementary-number-theory
ordinary-differential-equations
circles
derivatives
game-theory
definite-integrals
elementary-set-theory
limits
multivariable-calculus
geometry
algebraic-number-theory
proof-verification
partial-derivative
algebra-precalculus
Popular Questions
- What is the integral of 1/x?
- How many squares actually ARE in this picture? Is this a trick question with no right answer?
- Is a matrix multiplied with its transpose something special?
- What is the difference between independent and mutually exclusive events?
- Visually stunning math concepts which are easy to explain
- taylor series of $\ln(1+x)$?
- How to tell if a set of vectors spans a space?
- Calculus question taking derivative to find horizontal tangent line
- How to determine if a function is one-to-one?
- Determine if vectors are linearly independent
- What does it mean to have a determinant equal to zero?
- Is this Batman equation for real?
- How to find perpendicular vector to another vector?
- How to find mean and median from histogram
- How many sides does a circle have?
Apart from $1$, $2$, and $4$, the only numbers with primitive roots are the numbers of the shape $p^k$ or $2p^k$, where $p$ is an odd prime.
Once we have a primitive root $g$ for the odd prime $p$, finding primitive roots for $p^k$ and $2p^k$ is relatively cheap.
For $p^k$, we use the fact that if $g$ is a primitive root of $p$, then $g$ or $g+p$ is a primitive root of $p^k$ for all $k$.
So once we have found a primitive root $g$ of $p$, we test whether $g$ is a primitive root of $p^2$. If it is, we are finished. And if it is not, then we know $g+p$ is a primitive root of $p^k$ for all $k$.
As for $2p^k$, if $r$ is a primitive root of $p^k$ and $r$ is odd, then $r$ is a primitive root of $2p^k$. And if $r$ is even then $r+p^k$ is a primitive root of $2p^k$.