How is $\dfrac{4x}{x-3}$ equal to $4+\dfrac {12}{x-3}$?

Question

I am told that $\dfrac{4x}{x-3}$ is equal to $4+\dfrac {12}{x-3}$, but I have no idea how to arrive at that.

Can anyone, please, break it up for me?

Answer 1

\begin{equation*} 4+\frac{12}{x-3}=\frac{4(x-3)}{x-3}+\frac{12}{x-3}=\frac{4x-12+12}{x-3}=\frac{4x}{x-3} \end{equation*}