How is Euler's Formula Wrong?

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I figured out that if $x^{y} = z$, then $z^y = x^{y^2}$. Then we know Euler's Formula:

$$e^{πi} = -1,\quad (e^π)^i = -1,\quad (e^{2π})^i = 1$$

Now, using the formula above, let $e^{2π}$ act as x, and let i act as y. Then, finally, let 1 act as z. Accordingly, $z^{y}$, which is $1^i$, equals $x^{y^2}$, which is $(e^{2π})^{i^2}$. This means:

$$1^i = (e^{2π})^{-1}$$

Since $1^i = 1$:

$$1 = 1/(e^{2π})$$ $$(e^{2π}) = 1$$

But $(e^{2π}) ≠ 1$, so...(!!)

How is this possible?! And I think I actually figured this out!!!

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Exponents only behave well under certain conditions. For instance, when the base is a positive real number and the exponent is real, or when the base is non-zero and the exponent is an integer.

The more you move away from such requirements, the more careful you have to be when applying rules like $a^{b+c}=a^ba^c$ and $a^{bc}=(a^b)^c$. They will not always work.