How is it possible that $dx$ contains $dx^2$ $N$ and $N+1$ times simultaneously?

38 Views Asked by At

Let's assume that $N$ is even infinite hyperinteger and $N=1/dx$, $N=dx/dx^2$.

Let's assume that we have expression $dx+dx^2$. We can add up $dx^2$ to $dx$ and $dx$ is obtained: $dx+dx^2=dx$ (algebraic property of infinitisemals). So, $dx$ contains $dx^2$ $N$ times, but $(dx+dx^2)$ contains $dx^2$ $(N+1)$ times.

How is it possible that $dx$ contains $dx^2$ $N$ (even infinite hyperinteger) times and $N+1$(odd infinite hyperinteger) times simultaneously?

Thanks!