I'm not sure if I'm misunderstanding this in any way, but surely evaluating the zeta function at, say, -2, would give
$1 + 2^2 + 3^2 + 4^2 + 5^2 + ...$
which seems to diverge to infinity. What am I missing?
2026-03-30 17:37:08.1774892228
How is the Riemann zeta function zero at the negative even integers?
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