While studying for my English exam, I noticed that the way the definitions portion of the final is set up posed an interesting problem. While I will study all the definitions, I thought trying to solve this might be fun and just got totally stuck.
Given a list of 30 possible terms, 18 of them will be on the final exam; the final exam requires that I choose and define 10 of them. What is the minimum number of the terms I need to know so that for any 18 chosen, I know at least 10 words.
So far, I have found $$\alpha ={30 \choose 18}\cdot{18 \choose 10}$$ where $\alpha = 3.7847705 \times 10^{12}$.
My best guess for how to continue would be to find a number $$\beta = {30 \choose 18}\cdot{18 \choose k}$$ with $k \gt 10$ such that $$\frac{\beta}{\alpha} \le C$$ for some $C$.
My problem is that the discrete math I've seen thus far hasn't really told me how to proceed with a question like this, if there is a method, as I learned mostly about identities.
The problem can be answered simpler than that. The answer is that you need to learn $22$ words in order to guarantee knowing 10 in any selection of $18$.
We need to show that $22$ is sufficient and that anything less than $22$ won't always work.
To show that $22$ is sufficent, consider the worst case scenario: all $30 - 22 = 8$ words that you didn't study are part of the test. Then that means you know the remaining $10$ of those $18$ words, so you can pick those $10$ and all is well.
To show that anything less than $22$ isn't enough, consider this worst case scenario again. If you only learn $N$ terms, where $N < 22$, then the worst case scenario has $30 - N$ words you didn't study among the $18$ words, so $18- (30 - N) = N - 12$ words that you do know. You need $N - 12 \geq 10$, thus $N \geq 22$.