Taking one, two, three and four digits from digits $1,2,7$ and $8$, and if repetitions are not allowed
- How many different numbers can be arranged?
- How many of them would be greater than $200$?
I got the first answer $= 64$:
- $4$ one digit numbers
- $12$ two digit numbers
- $24$ three digit numbers
- $24$ four digit numbers
total $= 64$
How to know how many are above $200$ though?
Your calculations for the firs question are correct. For the second, any $4$ digit number is $>200$ and any three digit number that starts with $2,7$ or $8$. Hence, $3$ out of $4$ three digit numbers are above $200$, which gives you a total of $$24+\frac{3}{4}24=42$$ numbers above 200.