This was posed as an estimation problem - I'd be interested in both more accurate approximate methods (than my underestimate of 74 in the answer below) and a check of my exact answer (100, already verified in the comment section).
2026-03-27 12:02:51.1774612971
How many prime numbers contain strictly increasing digits?
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I originally estimated that there would be $74$ such numbers. This was based on counting the primes with $1,2$ and $9$ digits, and for $k=3,4,…8$, observing that there are $9 \choose k$ integers with $k$ strictly increasing digits and that each has roughly a $\frac1{\log x}$ probability of being prime, which I further rounded to $\frac{1}{2.3(k-1)}$. This gave roughly $4+11+17+18+14+7+2+1+0=74$.
I believe that there are exactly $100$ such numbers. This is based on the matlab code below. Sorting again by number of digits, this was $4+11+20+26+20+13+4+2+0$—the biggest error with my approximate model seems to be in $4–6$-digit numbers.