In a previous question, I learned that there exist infinitely many non biholomorphic Riemann surfaces homeomorphic to the torus.
Is it also true for the sphere?
In a previous question, I learned that there exist infinitely many non biholomorphic Riemann surfaces homeomorphic to the torus.
Is it also true for the sphere?
As stated in comments, the answer turns out to be an immediate consequence of the uniformization theorem:
So if $S$ is a Riemann surface homeomorphic to $\mathbb{S}^2$, it is simply connected, so biholomorphic to the open unit disk, the complex plane or the Riemann sphere. But a biholomorphism is a homeomorphism and neither the open disk nor the complex plane are homeomorphic to $\mathbb{S}^2$. Therefore, $S$ is biholomorphic to the Riemann sphere.