How many ways can we get exactly $2$ ones by rolling $6$ die ? ( Assuming order does matter )

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If the order doesn't matter then we can go this approach - Suppose we have $3$ die then there are $5$ ways to get exactly $2$ ones. Similarly for $4$ die there are $25$ ways. Going by this for $6$ die the answer is $625$ $(5^4)$. But I am unable to think what should my approach when order does matter.

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Your approach doesnt take into account the order. You need first to calculate the amount of diffrent places the 2 dices gets the value 1 There are 15 diffrent places the 2 dices who will get the value 1 Then for each place there is 5^4=625 as you written So in the end you got 15*625=9375 diffrent options.