How many ways can we put $5$ red balls, $4$ green balls and $3$ white balls into $12$ slots?
Would it be $12!$ or $\dfrac{12!}{5!4!3!}$? I'm confused here.
2026-04-13 03:14:41.1776050081
How many ways can we put $5$ red balls, $4$ green balls and $3$ white balls into $12$ slots?
1.2k Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail At
1
Since (red/green/white) balls are indistinguishable from other (red/green/white) balls, the answer is $\dfrac{12!}{5!4!3!}$, not $12!$.