I tried to generalize the question, but I have a concrete example to help specify the problem.
So let's say there's a group of tourists who like to visit 20 monuments of a city under 4 days. How many different ways can they do this, if they're able to visit all monuments in a day if they want so, and it matters, that on a given day in what order they visit them?
The problem reduces to partitioning of n elements into $k$ parts, which is by stars and bars $$ \binom{n+k-1}{n}. $$ The order can be imposed by all possible permutations of the $n$ elements. Thus the final answer is: $$ n! \binom{n+k-1}{n}. $$