How many ways to select 3 green balls in a row twice

Question

There are $12$ balls in the basket, $6$ green, and $6$ red. Each ball has a equal probability of getting selected. Now I randomly select the ball one at a time without order and without replacement. How many different ways can I select $3$ green balls in a row twice?

Answer 1

Identify the 3 green balls in a row as one object. So you would have 2 of those objects (since you want twice the 3 green balls in a row). So in total we have 8 objects now, 6 red balls and 2 green objects. So the amount of different ways to select the 2 green objects out of the total 8 objects would be $\binom{8}{2}=28$.