How many words exist that have exactly $5$ distinct consonants and $2$ identical vowels?

Question

I'm new to combinatorics, Although I understood most of the concepts this one baffles me.

How many words exist that have exactly $5$ distinct consonants and $2$ identical vowels?

The Answer is $$\binom{21}{5} \binom{5}{1} \frac{7!}{2!}$$

My doubt is: Why do we write $\binom{5}{1}$ when we have to select 2 vowels?(Answers with examples appreciated).

Answer 1

Since we have 2 identical vowels, we should to choose only one "kind" of vowels to put it in two places.

Answer 2

You are selecting 1 vowel (since your problem requires 2 identical ones) and then choosing where to place consonants and vowels in $7!/2!$ ways