I have these exponents which I wish to add together
$$10^{10^{200}} + 10^{10^{100}}$$
How do I add them such that the resulting exponent is in the form $a^{b^{a}}$ where $a$ and $b$ are positive integers?
I have these exponents which I wish to add together
$$10^{10^{200}} + 10^{10^{100}}$$
How do I add them such that the resulting exponent is in the form $a^{b^{a}}$ where $a$ and $b$ are positive integers?
I don't think this is possible. Note that $${10}^{10^{200}} ={10}^{10^{100\times 2}} ={10}^{(10^{100})^2} ={10}^{(10^{100})(10^{100})} =({10}^{10^{100}}) {}^{(10^{100})}. $$ So, knowing that $x^m+x=x(x^{m-1} +1)$, we get $${10}^{10^{200}} +{10}^{10^{100}} =({10}^{10^{100}}) {}^{(10^{100})} +{10}^{10^{100}} =({10}^{10^{100}}) \Big( {10}^{10^{100} -1} +1\Big). $$