Say if I have two sets of data, x and y. And I am required to apply a weighting factor,1/x, to the regression line. Does that mean I should plot 1/y versus 1/x and then get the regression? Could anyone help me with this please? Thanks.
2026-04-01 04:01:16.1775016076
how to apply weighting factor to linear regression
3.9k Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail At
1
There are 1 best solutions below
Related Questions in REGRESSION
- How do you calculate the horizontal asymptote for a declining exponential?
- Linear regression where the error is modified
- Statistics - regression, calculating variance
- Why does ANOVA (and related modeling) exist as a separate technique when we have regression?
- Gaussian Processes Regression with multiple input frequencies
- Convergence of linear regression coefficients
- The Linear Regression model is computed well only with uncorrelated variables
- How does the probabilistic interpretation of least squares for linear regression works?
- How to statistically estimate multiple linear coefficients?
- Ridge Regression in Hilbert Space (RKHS)
Trending Questions
- Induction on the number of equations
- How to convince a math teacher of this simple and obvious fact?
- Find $E[XY|Y+Z=1 ]$
- Refuting the Anti-Cantor Cranks
- What are imaginary numbers?
- Determine the adjoint of $\tilde Q(x)$ for $\tilde Q(x)u:=(Qu)(x)$ where $Q:U→L^2(Ω,ℝ^d$ is a Hilbert-Schmidt operator and $U$ is a Hilbert space
- Why does this innovative method of subtraction from a third grader always work?
- How do we know that the number $1$ is not equal to the number $-1$?
- What are the Implications of having VΩ as a model for a theory?
- Defining a Galois Field based on primitive element versus polynomial?
- Can't find the relationship between two columns of numbers. Please Help
- Is computer science a branch of mathematics?
- Is there a bijection of $\mathbb{R}^n$ with itself such that the forward map is connected but the inverse is not?
- Identification of a quadrilateral as a trapezoid, rectangle, or square
- Generator of inertia group in function field extension
Popular # Hahtags
second-order-logic
numerical-methods
puzzle
logic
probability
number-theory
winding-number
real-analysis
integration
calculus
complex-analysis
sequences-and-series
proof-writing
set-theory
functions
homotopy-theory
elementary-number-theory
ordinary-differential-equations
circles
derivatives
game-theory
definite-integrals
elementary-set-theory
limits
multivariable-calculus
geometry
algebraic-number-theory
proof-verification
partial-derivative
algebra-precalculus
Popular Questions
- What is the integral of 1/x?
- How many squares actually ARE in this picture? Is this a trick question with no right answer?
- Is a matrix multiplied with its transpose something special?
- What is the difference between independent and mutually exclusive events?
- Visually stunning math concepts which are easy to explain
- taylor series of $\ln(1+x)$?
- How to tell if a set of vectors spans a space?
- Calculus question taking derivative to find horizontal tangent line
- How to determine if a function is one-to-one?
- Determine if vectors are linearly independent
- What does it mean to have a determinant equal to zero?
- Is this Batman equation for real?
- How to find perpendicular vector to another vector?
- How to find mean and median from histogram
- How many sides does a circle have?
When you perform, say, a linear regression $y=a+bx$ based on the data points ($x_i,y_i$), if the $y_i$'s cover a large range, the largest values strongly contribute to define the parameters.
So, instead of minimizing $$SSQ=\sum_{i=1}^n (a+bx_i-y_i)^2$$ weighted least-square method minimize $$SSQ=\sum_{i=1}^n w_i(a+bx_i-y_i)^2$$ where $w_i$ is a weight assigned to each data point. In your case, $w_i=\frac 1 {x_i}$.
If you were using $w_i=\frac 1 {y_i^2}$, it would mean that you try to minimize the sum of squares of relative errors.
I suppose that what you are asked is to derive the formulae for $a,b$ when weights $w_i$ are used. Then, just write down the normal equations for $$SSQ=\sum_{i=1}^n \frac 1{x_i}(a+bx_i-y_i)^2$$ that is to say, compute $\frac{dSSQ}{da}$ and $\frac{dSSQ}{db}$; write that they are equal to zero. This will give two linear equations for the two unknowns $a$ and $b$.