How to build a $M = (f, B1, B2)$ matrix?

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So I'm given a linear transformation that goes like this:

$f: \mathbb R^3 \to \mathbb R^4$ such that $f(x,y,z)=(x+z, -y+z, x+y+2z, 2y)$

and $2$ bases:

$B_1 = ((1,0,2) , (2,0,3) , (1,1,0))$

$B_2 = ((2,0,2,1) , (2,0,3,1) , (1,1,0,2) , (0,1,1,1))$

and then I'm asked to build matrix $f$ relative to the bases $B_1$ and $B_2$, and I have no idea where to go from here.

Thanks, and excuse the lack of proper formatting, I'm in a bit of a hurry here, sorry.

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$B_1 = span \{u_1,u_2,u_3 \}$ and $B_2 = span \{v_1,v_2,v_3,v_4\}$

$f(u_1) = f(1,0,2) = (3,2,5,0)$

This is how $f$ maps the first vector in $B_1$ in terms of the standard basis in $\mathbb R^4$

Now we need to convert this into the basis $B_2$

$(3,2,5,0) = av_1 + bv_2 + cv_3 + dv_4$

Solve for $a,b,c,d.$

$f(u_1) = (1,-2,-1,3)$ in terms of the basis $B_2$

$f(u_2) = (5,3,8,0), f(u_3) = (1,-1,2,2)$ again in terms of the standard basis.

$f(u_2) = (3,-1,-2,3), f(u_3) = (7,13,-2,-9)$ in terms of the basis $B_2$

$f:B_1\to B_2$

$f(x_1,x_2,x_3) = (x_1 + 3x_2 + 7x_3, -2x_1 - x_2 + 13x_3, -x_1-2x_2-2x_3, 3x_1 +3x_2 - 7x_3)$