How can I take the following integral?
$$\int x d(4x) $$
It seems very easy. But it is difficult for me.
Is it equal to $4\times \frac12 \times x^2+c$ ?
How can I take the following integral?
$$\int x d(4x) $$
It seems very easy. But it is difficult for me.
Is it equal to $4\times \frac12 \times x^2+c$ ?
Yes, of course! It's $$4\int xdx=4\cdot\frac{x^2}{2}+C=2x^2+C$$