how to calculate this line integral $\int_{0}^{2\pi} (16\sin^2 3t +16\cos^2 4t)\sqrt{(144\cos^2 3t +256\sin^2 4t)}dt$

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I am working on a line integral to calculate the amount of chocolate to cover a pretzel. the density of the pretzel is given by this formula $\lambda=3(x^2+y^2)$ and the parameter equation of a pretzel shape is given by

$$x(t)=-4\sin 3t \quad\text{and}\quad y(t)=4\cos4t$$

apply the mass formula $\int_C \rho (x,y)\,ds$

I get

$$\int_0^{2\pi}\left((16\sin^2 3t +16\cos^2 4t)\sqrt{144\cos^2 3t +256\sin^2 4t}\right) \,dt$$

then I have no idea how calculate this line integral.

can anyone give me a hint? Thanks!