how to derive the trigonometric polynomial in Fourier approximation

178 Views Asked by At

in the red square part of the formula, I have no idea how it becomes $\frac{1}{2\Pi}$ and also what does "function 1" mean? I find this description very confusing and unclear. please give me some direction to grasp it.

enter image description here

1

There are 1 best solutions below

2
On

Do you know what's a constant map is ? If you do, treat $1$ as a constant map with the constant being one. And $1/{2 \pi}$ is the normalizing term. In the second equality, they isolated the term in the square braces because that's exactly what the Fourier coefficient is on the interval $[0, 2 \pi].$