So apparently $\frac{n+(-1)^n}{n}=1+\frac{(-1)^n}{n}$ and when $n=1$, the sequence is $0$. So it is bounded below by $0$. But how can you sure about the upper bound?
2026-04-02 05:01:11.1775106071
How to determine the boundedness for sequence $\frac{n+(-1)^n}{n}$?
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$\frac{n+(-1)^n}{n}\leq \frac{n+1}{n}=1+\frac{1}{n}\leq 2$.