for instance the particular solution of a homogeneous SDE is given by ,
It looks like a spiral to me. But I cant explain why this is not a centre? Since centre and spirals contain sine and cosine parts.
Show that $y_1(t)^2+y_2(t)^2=13$ for all $t$. This shows that each pair $(y_1(t),y_2(t))$ lies on the circle $C=\{(x,y) \in \mathbb R^2: x^2+y^2=13\}.$
Copyright © 2021 JogjaFile Inc.
Show that $y_1(t)^2+y_2(t)^2=13$ for all $t$. This shows that each pair $(y_1(t),y_2(t))$ lies on the circle $C=\{(x,y) \in \mathbb R^2: x^2+y^2=13\}.$