My friend asked me to help solve a problem in which she cannot use a calculator.
$$ \require{enclose} \begin{array}{r} 32.45 \enclose{longdiv}{253.11} \\[-3pt] \end{array} $$
What is the best method to approach this in an exam situation - i.e. relatively quickly?
Thanks for your help.
May be $$32.45=\frac{3245}{100}=\frac{5 \times 11 \times 59}{100}$$ $$253.11=\frac{25311}{100}=\frac{3 \times 11 \times 13 \times 59}{100}$$ could help to get $$\frac{32.45}{253.11}=\frac 5{39}$$ $$\frac{253.11}{32.45}=\frac {39}5=\frac {78}{10}=7.8$$